Physics Topic 9: Motion in Fields

The IB 2009 Physics HL Objectives

22 cards   |   Total Attempts: 182
  

Cards In This Set

Front Back
9.1.1 State the independence of the vertical and the horizontal components of velocity for a projectile in a uniform field
² Projectile: body moving in free motion ² Free motion has gravity and air resistance n Air resistance/friction: negligible n Gravity: downward force ² Horizontal velocity: 0 (no force) ² Vertical velocity: accelerating downward (gravity) ² Result in parabola
9.1.2 Describe and sketch the trajectory of projectile motion as parabolic in the absence of air resistance.
Answer 2
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9.1.3 Describe qualitatively the effect of air resistance on the trajectory of a projectile.
² Shorter range ² Lower height Why? Air resistance against the velocity of the trajectory
9.2.1 Define gravitational potential and gravitational potential energy
Gravitational Potential: ² Work done per unit mass to bring a point mass from infinity to that point Gravitational Potential Energy: ² Energy needed to perform gravitational potential Gravitational Constant: 6.67 * 10-11 Nm2kg-2
9.2.2 State and apply the expression for gravitational potential due to a point mass
Answer 5
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9.2.3 State and apply the formula relating gravitational field strength to gravitational potential gradient
Gravitational Field Strength (I)= - ΔV / Δx
9.2.4 Determine the potential due to one or more point masses
Answer 7
V = -G {(M1 / x) + (M2 / r-x)}
9.2.5 Describe and sketch the pattern of equipotential surfaces due to one and two point masses
Answer 8
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9.2.6 State the relation between equipotential surfaces and gravitational field lines
Gravitational lines ⊥ equipotential surface
9.2.7 Explain the concept of escape speed from a planet
² The minimum initial speed at surface of a body required to escape a body’s gravitational field. ² M IS BEG: Minimum Initial Speed for Body to Escape Gravitational field
9.2.8 Derive an expression for the escape speed of an object from the surface of a planet
|KE| = |PE| |0.5mvescape2| = |-GMem/Re| vescape = √2GM/R vescape on earth = √2g0Re
( g0 = GMe / Re2)
9.3.1 Define electric potential and electric potential energy
Answer 12
Electrical potential at a point in a field: ² Work done per unit charge in bringing a positive test charge from infinity to the point in the field. V = ,k∗point charge-distance from point charge. ² Electrical potential energy of a point charge at any point: Work done in moving the charge from infinity to that point
9.3.2 State and apply the expression for electric potential due to a point charge
Answer 13
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9.3.3 State and apply the formula relating electric field strength to electric potential gradient
Potential gradient: Work done to move a charge from one potential to another
= qΔV W = FΔx FΔx = qΔV = −,△V-△x.
9.3.4 Determine the potential due to one or more point charges
Answer 15
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